compareTo 可用來比較兩字串是否相同,它屬於 Class String。當回傳值為0時,表示兩字串相等。
範例
String string1;
String string2;
if (string1.compareTo(string2) == 0)
兩字串相等
else
兩字串不相等
compareTo
public int compareTo(String anotherString)
Compares two strings lexicographically. The comparison is based on the Unicode value of each character in the strings. The character sequence represented by thisStringobject is compared lexicographically to the character sequence represented by the argument string. The result is a negative integer if thisStringobject lexicographically precedes the argument string. The result is a positive integer if thisStringobject lexicographically follows the argument string. The result is zero if the strings are equal;compareToreturns0exactly when theequals(Object)method would returntrue.This is the definition of lexicographic ordering. If two strings are different, then either they have different characters at some index that is a valid index for both strings, or their lengths are different, or both. If they have different characters at one or more index positions, let k be the smallest such index; then the string whose character at position k has the smaller value, as determined by using the < operator, lexicographically precedes the other string. In this case,compareToreturns the difference of the two character values at positionkin the two string -- that is, the value:
If there is no index position at which they differ, then the shorter string lexicographically precedes the longer string. In this case,this.charAt(k)-anotherString.charAt(k)
compareToreturns the difference of the lengths of the strings -- that is, the value:this.length()-anotherString.length()
- Specified by:
compareToin interfaceComparable<String>- Parameters:
anotherString- theStringto be compared.- Returns:
- the value
0if the argument string is equal to this string; a value less than0if this string is lexicographically less than the string argument; and a value greater than0if this string is lexicographically greater than the string argument.
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